Grade 4 Academic Math U11L4HW1
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- Question 1 of 13
1. Question
1a. Find the perimeter of the rectangle
2 x Length = 2 x 12 in = in
2 x Width = 2 x 8 in = in
Perimeter= + = in
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2. Question
1b. Find the perimeter of the rectangle
Length+ Width= 12 + 8 = in
Perimeter = 2 x = in
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3. Question
2a. A rectangle has a perimeter of 26 cm and a width of 5 cm. Find the length of the rectangle.
Length+ Width= 26 ÷ 2 = cm
Length= – = cm
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4. Question
2b. A rectangle has a perimeter of 26 cm and a width of 5 cm. Find the length of the rectangle
2 x Length = 26 – = cm
Length= ÷ 2 = cm
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5. Question
3. A square has a perimeter of 36 in. What is the area of the square?
4 x Length of side = 36 in
Length of side = 36 ÷ 4 = in
Area = x = in$^2$
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6. Question
4a. Find the unknown lengths
in
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7. Question
4b. Find the unknown lengths
cm
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8. Question
5. In the figures below, the square and the rectangle have the same area. The perimeter of the square is 40 cm. What is the length of the rectangle?
cm
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9. Question
6a. The perimeter of a tennis court is 228 feet. The width of the court is 12 yards.
What is the length of the court in feet?ft
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10. Question
6b. The perimeter of a tennis court is 228 feet. The width of the court is 12 yards.
What is the length of the court in yards?yd
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11. Question
7a. The perimeter of a painting is 18 ft. The width of the painting is 4½ ft.
What is the length of the painting in feet?ft
Your answer should be
a proper fraction like 1/2 or 3/10
an improper fraction like 10/7 or 14/8
In simplest form
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12. Question
7b. The perimeter of a painting is 18 ft. The width of the painting is 4½ ft.
What is the length of the painting in inches?in
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13. Question
8. The perimeter of a rectangular picture frame is 70 in. The length of the frame is 1 ft 8 in. What is the width of the frame in feet and inches?
ft in
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